Question

find 4 consecutive terms in arithmetic progression whose sum is 88 and the sum of first and third term is 40

Answer 1

Answer:16, 20, 24, 28

Step-by-step explanation:

S4 = 88

4/2 (2a + 3d) = 88

2a + 3d = 44 (1)

a1 + a3 = 40

a + a + 2d = 40

2a + 2d = 40

from (1) & (2),

d = 4

putting in (2),

2a + 8 = 40

2a = 32

a = 16



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