find 4 no. in AP such that their sum is 50 and in which greater no. is 4 times least
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Let the 4 numbers are a , a + d , a + 2d , a + 3d. Sum of 4 numbers AP = 50
a + a + d + a + 2d + a + 3d = 50
⇒ 4a + 6d = 50
⇒ 2a + 3d = 25 --------------(1)
Also given the greatest number is 4 times the least.
4(a) = a + 3d
4a - a = 3d
a = d
putting a = d in (1) , we obtain
5d = 25
d = 5
a = 5 but d = a.
∴ First four terms are 5 , 10 ,15 , 20
a + a + d + a + 2d + a + 3d = 50
⇒ 4a + 6d = 50
⇒ 2a + 3d = 25 --------------(1)
Also given the greatest number is 4 times the least.
4(a) = a + 3d
4a - a = 3d
a = d
putting a = d in (1) , we obtain
5d = 25
d = 5
a = 5 but d = a.
∴ First four terms are 5 , 10 ,15 , 20
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