Question

Find 4 number in A.P. such that their sum is 44 and the product of first and last is 85​

Answer 1

Answer:

Therefore the four numbers in A.P are 5, 8, 14 and 17

Step-by-step explanation:

Let the numbers be a−2d,a−d,a+d and a+2d

According to the question it is give that

a−2d+a-d+a+d+a+2d=44

4a=44

a=11

it is also given that,

(a−2d)(a+2d)=85

a^2 +2ad−2ad−4d^2=85

a^2−4d^2 =85

a^2−85=4d^2

11^2−85=4d^2

121−85=4d^2

4d^2=36

d^2=9

d=3

a-2d=11-6=5

a−d=11-3=8

a+d=11+3=14

a+2d=11+6=17

Answer 2

The four numbers are :

1st number = a-3d = 11-6 (6) = 11-12 = 1.

2nd number = a-d = 11-6 = 5.

3rd number = a+d = 11+6 = 17.

4th number = a+3d = 11+6 (6) = 11+12 = 23.

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