Math, asked by djgaming26, 5 months ago

find 4 solutions of x+3y=5 plot in graph​

Answers

Answered by sainlab1980
0

Answer:

Answer: x=1

Answer: x=1x+3y=5

Answer: x=1x+3y=5subsitute the value of x

Answer: x=1x+3y=5subsitute the value of x1+3y=5

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-1

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=5

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-2

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=5

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-3

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-33y=2

Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-33y=2y=2/3

I hope this help ful u..

Answered by tanishakhatri2236
0

Answer:

i) (-1,2)

ii) (8,-1)

iii) (5,0)

iv) (-7,4)

Step-by-step explanation:

x+3y=5

i)= x=5-3y

let the value of y= 2

so x= 5-3*2

= 5-6

= (-1)

= x,y= (-1,2)

ii) x=5-3y

let the value of y= (-1)

x= 5-3*(-1)

x= 5-(-3)

x=5+3

x=8

so x,y= (8,-1)

iii)x=5-3y

now let the value of y= 0

x=5-3*0

x=5-0

x=5

x,y= (5,0)

iv) x=5-3y

let the value of y=4

x=5-3*4

x=5-12

x=(-7)

x,y=(-7,4)

hope it helps u...Pls mark my answer as Brainliest

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