find 4 solutions of x+3y=5 plot in graph
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Answered by
0
Answer:
Answer: x=1
Answer: x=1x+3y=5
Answer: x=1x+3y=5subsitute the value of x
Answer: x=1x+3y=5subsitute the value of x1+3y=5
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-1
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=5
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-2
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=5
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-3
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-33y=2
Answer: x=1x+3y=5subsitute the value of x1+3y=53y=5-13y=4y=4/3x=2x+3y=5subsitute the value of x2+3y=53y=5-23y=3y=3/3y=1x=3x+3y=5subsitute the value of x3+3y=53y=5-33y=2y=2/3
I hope this help ful u..
Answered by
0
Answer:
i) (-1,2)
ii) (8,-1)
iii) (5,0)
iv) (-7,4)
Step-by-step explanation:
x+3y=5
i)= x=5-3y
let the value of y= 2
so x= 5-3*2
= 5-6
= (-1)
= x,y= (-1,2)
ii) x=5-3y
let the value of y= (-1)
x= 5-3*(-1)
x= 5-(-3)
x=5+3
x=8
so x,y= (8,-1)
iii)x=5-3y
now let the value of y= 0
x=5-3*0
x=5-0
x=5
x,y= (5,0)
iv) x=5-3y
let the value of y=4
x=5-3*4
x=5-12
x=(-7)
x,y=(-7,4)
hope it helps u...Pls mark my answer as Brainliest
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