Question

find 4terms of sequence -6n+100​

Answer 1

Answer:

Let (a) (a+d) (a+2d) (a+3d) be the 4arthemetic series

then,S4 (4/2) (2a+(4-1)d)

100=2(2a+3d)

2a+3d=50........(1)

let d=2

then a= 22

therefore series is 22,24,26,28

put d=2,4,6.....16