find 4x²+y²+z²-4xy-2yz+4xz
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(2x + y + z )^2...........
Magan1120:
hole sum I need it
Answered by
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Hey sup!
We'll use the formula,
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca.
As per the question,
4x^2 +y^2 + z^2 -4xy-2yz+4xz.
=(2x)^2+(-y)^2+z^2+2*2x*(-y)+2*(-y)*z+2*2x*z.
=(2x-y+z)^2.
Hope it helps
We'll use the formula,
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca.
As per the question,
4x^2 +y^2 + z^2 -4xy-2yz+4xz.
=(2x)^2+(-y)^2+z^2+2*2x*(-y)+2*(-y)*z+2*2x*z.
=(2x-y+z)^2.
Hope it helps
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