Math, asked by Magan1120, 1 year ago

find 4x²+y²+z²-4xy-2yz+4xz

Answers

Answered by sru8
1
(2x + y + z )^2...........

Magan1120: hole sum I need it
Answered by kushanaanandp4ac8a
4
Hey sup!

We'll use the formula,
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca.

As per the question,

4x^2 +y^2 + z^2 -4xy-2yz+4xz.
=(2x)^2+(-y)^2+z^2+2*2x*(-y)+2*(-y)*z+2*2x*z.
=(2x-y+z)^2.

Hope it helps
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