find 5 fractions between 1/6 and 1/5
DaIncredible:
hay is this a question of number system
Answers
Answered by
2
Let x=1/6, y=1/5 & n=5.
Let d=(y-x)/(n+1) = 1/180
Then, required fractions are:
(x+d), (x+2d), (x+3d), (x+4d), (x+5d)
i.e., (1/6+1/180), (1/6+2/180),(1/6+3/180),(1/6+4/180),(1/6+5/180).
i.e., 31/180, 8/45, 11/60, 17/90, 7/36.
Hence, the required fractions between 1/6 & 1/5 are: 31/180, 8/45, 11/60, 17/90 & 7/36.
I hope it will help you. Please mark my answer as brainliest.
Let d=(y-x)/(n+1) = 1/180
Then, required fractions are:
(x+d), (x+2d), (x+3d), (x+4d), (x+5d)
i.e., (1/6+1/180), (1/6+2/180),(1/6+3/180),(1/6+4/180),(1/6+5/180).
i.e., 31/180, 8/45, 11/60, 17/90, 7/36.
Hence, the required fractions between 1/6 & 1/5 are: 31/180, 8/45, 11/60, 17/90 & 7/36.
I hope it will help you. Please mark my answer as brainliest.
Attachments:
Answered by
1
Hey friend,
the answer is:
First,
(1/5 + 1/6) ÷ 2 = 11/30 ÷ 2
11/30 × 1/2
11/60
So the 1st no. is
11/60
Similarly
Now we have to find no. between
1/6 and 11/60
So,
(1/6 + 11/60) ÷ 2
(10/60 + 11/60) ÷ 2
21/60 ÷ 2
21/60 × 1/2
21/120
So, the second no. is
21/120
Now,
by similar method we have to find no. between 11/60 and 1/5
So, the answer will be 23/120
Similarly no. between 23/120 and 1/5 will be,
47/240.
And between 1/6 and 21/120 will be 41/240
So our final answer will be
1/6 , 42/240 , 21/120 , 11/60 , 23/120 , 47/240 , 1/5
HOPE MY ANSWER WOULD BE HELPFUL TO YOU!!!!!!☺☺.
the answer is:
First,
(1/5 + 1/6) ÷ 2 = 11/30 ÷ 2
11/30 × 1/2
11/60
So the 1st no. is
11/60
Similarly
Now we have to find no. between
1/6 and 11/60
So,
(1/6 + 11/60) ÷ 2
(10/60 + 11/60) ÷ 2
21/60 ÷ 2
21/60 × 1/2
21/120
So, the second no. is
21/120
Now,
by similar method we have to find no. between 11/60 and 1/5
So, the answer will be 23/120
Similarly no. between 23/120 and 1/5 will be,
47/240.
And between 1/6 and 21/120 will be 41/240
So our final answer will be
1/6 , 42/240 , 21/120 , 11/60 , 23/120 , 47/240 , 1/5
HOPE MY ANSWER WOULD BE HELPFUL TO YOU!!!!!!☺☺.
Similar questions