Find 60 th term of ap -20,-15,-10....... if it has total 60 terms and hence find the sum of last ten term.
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Hey Mate ✌
Here's your answer friend,
Given : A.P. ==> -20, -15, -10 ...an
Here, Total terms (n) = 60
first term a = -20
Common difference = (-15)-(-20) = -15 + 20
(d) = 5
==> 60th term = a60 = a + 59d
==> -20 + 59(5) = -20 + 295
==> a60 = 275
Thus, 60th term of the A.P. is 275.
Now, let us invert the A.P.
We get,
==> 295, 290, 285,............-20
==> Now here first term a = 295
==> common difference d = 5
==> last term (L) = (-20)
Now sum of ten terms
Sn = n/2 (a + l)
==> S10 = 10/2 (295 + (-20))
==> S10 = 5 (275)
==> 1375
Thus, sum of last ten terms of the given Arithmetic Progression is 1375.
⭐ Hope it helps you ^_^ ⭐
Here's your answer friend,
Given : A.P. ==> -20, -15, -10 ...an
Here, Total terms (n) = 60
first term a = -20
Common difference = (-15)-(-20) = -15 + 20
(d) = 5
==> 60th term = a60 = a + 59d
==> -20 + 59(5) = -20 + 295
==> a60 = 275
Thus, 60th term of the A.P. is 275.
Now, let us invert the A.P.
We get,
==> 295, 290, 285,............-20
==> Now here first term a = 295
==> common difference d = 5
==> last term (L) = (-20)
Now sum of ten terms
Sn = n/2 (a + l)
==> S10 = 10/2 (295 + (-20))
==> S10 = 5 (275)
==> 1375
Thus, sum of last ten terms of the given Arithmetic Progression is 1375.
⭐ Hope it helps you ^_^ ⭐
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