Question

find 7/18 -11/36

$1810}{?}$
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Answer 1

Answer:

2a- LCM of 18 and 36=36

therefore

$\frac{14 - 11}{36} = \frac{3}{36} = \frac{1}{12}$

2b-

$\frac{ - 3}{8} \div \frac{9}{4} = \frac{ - 3 \times 4}{9 \times 8} = \frac{ - 12}{72} = \frac{ - 1}{ - 6} = \frac{1}{6}$

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Answer 2

To find : $\frac{7}{18} - \frac{11}{36}$

Solution:

• To find the difference of given rational numbers we get need to equalize denominators of both the rational numbers. By taking LCM

• Therefore, LCM = $36$

• Now, multiplying numerators of both rational numbers by same number as multiplied by denominators to make LCM.

• Therefore, we get,

•  $\frac{7}{18} - \frac{11}{36}$

        $\frac{7}{18}-\frac{11}{36}=\frac{7 \times 2}{36}- \frac{11 \times 1}{36}$

                     $= \frac{14 - 11}{36}\\= \frac{3}{36} \\= \frac{1}{12}$

Hence, difference of $\frac{7}{18}$ and $\frac{11}{36}$  is $\frac{1}{12}$ .