Question

FinD.....................

Answer 1

$\huge{\bold{\red{(1)Zero}}}$

At the centre of earth, value of g is zero. As the acceleration due to gravity is zero at the centre of earth, weight of a body is zero at thecentre of earth.

$\huge{\bold{\red{(2)Height=Radius\: of\: Earth}}}$

We have the formula,

g' = g/(1+h/R)^2

Here g' = acceleration due to gravity at the height

g = 9.8m/s^2

R = radius of earth

h = height

on Putting the value, we get

g/g' = (1+h/R)^2

4 = (1+h/R )^2

1+h/R = 2

h/R = 1

h = R

R=6371 Km