Question

find 7th and 8th term of geometric progression 3,6,12 etc

Answer 1

a=3
r=6/3=2
T7 = ar^n-1=3*2^6=3*64=192
T8=ar^n-1=3*2^7=3*128=384

Answer 2

Progression is 3, 6, 12, .......

$a=3,\ r= \frac{6}{3}=2 \\ \\a_n=ar^{n-1}\\a_7=3 \times 2^{7-1}=3 \times 2^6=3 \times 64=192\\a_8=3 \times 2^{8-1}=3 \times 2^7=3 \times 128=384$