Question

Find 8th term of GP . 1, 2, 4,....​

Answer 1

Answer:

8th term of this GP is 128

Solution :

First term of GP (a) = 1

Common Difference = $\sf \frac{Second \: term }{first \: term}$

$= \frac{2}{1} \\ = \red{ \boxed{ \green{2}}}$

◇ We have to find the Value of 8th Term !

We know that nth term of GP is $\sf \: T_{n} = ar{}^{(n - 1)}$ , Where a is First term of the GP, r is Common Difference.

So,

• a = 1
• r = 2
• n = 8

Put these given Values in this given Formula we get ,

$\rightarrow \: \boxed{\sf \: T _{n} = ar {}^{(n - 1)}} \\ \rightarrow \: \sf T_{(8)} = 1 \times 2 {}^{(8 - 1)} \\ \rightarrow \sf \: T _{(8)} = 2 {}^{7} \\ \rightarrow \: \sf \red{ \boxed{ \green{ \sf \: T_{(8)} = 128}}}$

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