Question

Find [8x dx in (0,1)​

Answer 1

Question:

I assume you're trying to ask this:

$\\\tt \int\limits^0_1 {8x} \, dx$

Answer:

4

Step-by-step explanation:

$\\\tt \int\limits^1_0 {8x} \, dx \\=[ \dfrac{8x^2}{2} ] ^{1} _{0} \\ = [ 4x^2 ] ^{1} _{0}\\= 4(1^2) - 4(0^2)\\=4$