Question

Find 8xy(x² + y²) when x+y = 5 and x-y = 1​

Answer 1

Step-by-step explanation:

x+y = 5 ........[1]

x-y = 1..........[2]

Adding these equations

2x = 6

x = 3

Put x = 3 in equation 1, we get

3 + y = 5

y = 2.

now, consider

$8xy( {x}^{2} + {y}^{2} ) \\ = 8 \times 3 \times 2( {3}^{2} + {2}^{2} ) \\ = 48 \times (9 + 4) \\ = 48 \times 13 \\ = 624$

Answer 2

Answer:

this is correct..................