Find a 2 digit number with 5 in the ones place. When 27 is added to the numbers the digits are reversed
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Let the tens digit be x
Given that ones digit is 5
Original no =10x+5
No. Obtained when digits are reversed=50+x
Given that 10x+5+27=50+x
10x+32=50+x
10x-x=50-32
9x=18
x=18/2
x=9
Hence the no. Is 10x+5
10*9+5=90+5=95
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