Math, asked by jaisingadi5279, 1 year ago

Find a 2 digit number with 5 in the ones place. When 27 is added to the numbers the digits are reversed

Answers

Answered by Anonymous
3

Let the tens digit be x

Given that ones digit is 5

Original no =10x+5

No. Obtained when digits are reversed=50+x

Given that 10x+5+27=50+x

10x+32=50+x

10x-x=50-32

9x=18

x=18/2

x=9


Hence the no. Is 10x+5

10*9+5=90+5=95

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