Find a and b 5+root3/7-4root3=47a+root3b
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Answer:
Step-by-step explanation:
5+√3/(7-4√3)
→ 5+√3/7-4√3 × 7+4√3/7+4√3
→ (5+√3)(7+4√3)/(7-4√3)(7+4√3)
→ 5(7+4√3)+√3(7+4√3)/{7²-(4√3)²}
→ 35+20√3+7√3+4(3)/(49-16(3))
→ 35+20√3+7√3+12/(49-48)
→ 47+27√3/1
→ 47+27√3 = 47a+√3b
Therefore,by comparing we can say that
a = 1 and b = 27
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simmikaur0730:
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