# find a and b if 3+√2/3 -√2=a+b√2

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Solving

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By rationalization,

Comparing values,

I hope this will help you

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Answered by

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Heya ✋

Let see your answer !!!!!

Given that

3 + √2 / 3 - √2 = a + b√2

Solution

(3 + √2) × (3 + √2) / (3 - √2) × (3 + √2)

= (3 + √2)^2 / (3)^2 - (√2)^2

= (3)^2 + (√2)^2 + 2 × 3 × √2 / 9 - 2

= 9 + 2 + 6√2 / 7

= 11 + 6√2/7

= 11/7 + 6√2/11

On getting the values

a = 11/7

b√2 = 6√2/11

b = 6/11

Thanks :))))

Let see your answer !!!!!

Given that

3 + √2 / 3 - √2 = a + b√2

Solution

(3 + √2) × (3 + √2) / (3 - √2) × (3 + √2)

= (3 + √2)^2 / (3)^2 - (√2)^2

= (3)^2 + (√2)^2 + 2 × 3 × √2 / 9 - 2

= 9 + 2 + 6√2 / 7

= 11 + 6√2/7

= 11/7 + 6√2/11

On getting the values

a = 11/7

b√2 = 6√2/11

b = 6/11

Thanks :))))

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