find a and b if root2 + root3 / 3 root2 - 2 root3 =a-b root6
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sahil332627:
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Here is your answer
root 2+root 3/3root2-2rot3
(root2+root3* 3root2-2root3)÷ ( 3root2-2root3× 3root2+2root3)
= 12+5root6/6
on comparing lhs with rhs.
we will get,
a = 2 and b = -5/6
root 2+root 3/3root2-2rot3
(root2+root3* 3root2-2root3)÷ ( 3root2-2root3× 3root2+2root3)
= 12+5root6/6
on comparing lhs with rhs.
we will get,
a = 2 and b = -5/6
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