find a and b in the image above
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4+√2/ 4-√2
by rationalising
(4+√2) ( 4+√2) / (4-√2)(4+√2)
(4+√2)²/ (4)² - (√2)²
[ (a+b)²= a²+b²+2ab] & [(a+b)(a-b)=a² - b²]
((4)²+(√2)²+2×4×√2) /16-2
16+2+8√2 / 14
18+8√2 / 14 = a -√b
9/7 +4√2/7 = a-√b
a= 9/7
-√b =4√2/7
-b = (4√2/7)²
b= -32/49
by rationalising
(4+√2) ( 4+√2) / (4-√2)(4+√2)
(4+√2)²/ (4)² - (√2)²
[ (a+b)²= a²+b²+2ab] & [(a+b)(a-b)=a² - b²]
((4)²+(√2)²+2×4×√2) /16-2
16+2+8√2 / 14
18+8√2 / 14 = a -√b
9/7 +4√2/7 = a-√b
a= 9/7
-√b =4√2/7
-b = (4√2/7)²
b= -32/49
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