Question

Find a and b plz fast

Answer 1

Answer:

hope it will help you:-)

Answer 2

Answer:

$\frac{\sqrt{2}+\sqrt{3}}{3\sqrt{2}-2\sqrt{3}}$

rationalize the denominator

$\frac{\sqrt{2}+\sqrt{3}}{3\sqrt{2}-2\sqrt{3}}$ × $\frac{3\sqrt{2}+2\sqrt{3}}{3\sqrt{2}+2\sqrt{3}}$

=$\frac{6+2\sqrt{6}+3\sqrt{6}+6}{(3\sqrt{2})^2-(2\sqrt{3})^2}$

=$\frac{12+5\sqrt{6}}{18-12}$

=$\frac{12+5\sqrt{6}}{6}$

=$\frac{6(2+\frac{5}{6}\sqrt{6})}{6}$

=2+$\frac{5}{6}\sqrt{6}$

a-b$\sqrt{6}$=2-(-$\frac{5}{6}\sqrt{6}$)

a=2

b=-$\frac{5}{6}$

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