find a and b so that given numbers are divisible by both 3 and 5 a)7b25 b)8ab46
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Answered by
2
Answer:
b=1,4,7 for option (a)
I think your option (b) is wrong because its last digit is 6 and hence it is not divisible by 5
sahin39:
b) 8ab46 find
this is only tru for 3 but not for 5
ok second question is wrong aisa tha second question b)8ab46 find out
as last digit is 6 so you never may divide it by 5 for any values of a &b
ha
Answered by
0
Answer:
a)b=7,1,4
it is just simple observation .
b) for any values "a" & "b" is not divided by 5
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