find a and b so that x^2-1 is a factor of x^4 + ax^3+ 2x^2- 3x+ b
Gulabharnakiya:
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to solve this we have to solve value of x from the given factor, then put the value in the polynomial

so value of x= -1 and +1



on adding both equation,we get

put the value of B in any equation for value of a

so these are the values of a and b.
hope it may help you.
so value of x= -1 and +1
on adding both equation,we get
put the value of B in any equation for value of a
so these are the values of a and b.
hope it may help you.
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