find a and b so that x2-1 is the factor of x4+ax3+2x2-3x+b
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if your question is 2x-1 is a factor of 4x+3a+4-3x+b then 3a+b= - 4 whole and a half.because if 2x-1 is a factor 2x-1=0,x=1/2.
4x+3a+4-3x+b=0.
substituiting the value of x
then, 6-3/2+3a+bb=0
3a+b=-9/2
therefore, b = -9/2-3a
and a=(-9/2-b)/3
4x+3a+4-3x+b=0.
substituiting the value of x
then, 6-3/2+3a+bb=0
3a+b=-9/2
therefore, b = -9/2-3a
and a=(-9/2-b)/3
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