Question

if momentum of a particle is increased by 60% then percentage increase in its kinetic energy is

Answer 1

The mass of the particle remains same. that means the 60% increase in momentum is 60% increase in velocity.
so the new velocity is 1.6 times of intial velocity
the kinetic energy is proportional to the square of velocity so the new kinetic energy is 1.6^2 =2.56 times of initial K.E.
so the net change in K.E. is 1.56 times of initial K.E.

thus the change is K.E. is 156%

Answer 2

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