Question

Find a and b such that 12, a + b , 2a, b are in AP.

Answer 1

since the given terms are in A.P,

then

2(a+b)=12+2a,

2a+2b=12+2a,

2b=12,

then

b=6,

also

2×2a=a+b + b,

4a=a+6+6,

4a-a=12,

3a=12,

then

a=4

Answer 2

$\huge{Hey mate!}$ Here is your answer. I hope it helps

a=12
a+d=a+b
a+2d=2a
a+3d=b

12+d=a+b
d=a+b-12 ------- (¡)

a+b+d=2a
a+b+(a+b-12)=2a
a+b+a+b-12=2a
2a+2b-12=2a
a+b-6=a
a-a+b=6
b=6 ------------(¡¡)

4th term= b=6

2a+d=b
2a+a+b-12=6
3a+6-12=6
3a-6=6
3a=12
a=12/3
a=4


A=4
B=6


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