plz give answer to this question
Attachments:
Answers
Answered by
1
Hey friend your answer.........
√p/q= (q/p)^1-2x
(p/q)^1/2 = (q/p)^1-2x
(q/p)^-1/2 = (q/p)^1-2x
here base is same (q/p)
so,
comparing the powers------
-1/2 = 1-2x
-1/2 -1 = -2x
-3/2 = -2x
3/2=2x
x =3/2×2
x=3/4
~~~~~~
I hope it helps you
√p/q= (q/p)^1-2x
(p/q)^1/2 = (q/p)^1-2x
(q/p)^-1/2 = (q/p)^1-2x
here base is same (q/p)
so,
comparing the powers------
-1/2 = 1-2x
-1/2 -1 = -2x
-3/2 = -2x
3/2=2x
x =3/2×2
x=3/4
~~~~~~
I hope it helps you
saimakhanJNS:
Thanks for giving answer
Similar questions