Question

Find A as Required:
1.the greatest 2 digit no 9A is divisible by 2.
2.the least no 567A is divisible by 3.
3.the greatest 3 digit no 9A6 is divisible by 6.
4.the no A08 is divisible by 4 and 9.
5.the no 225A85 is divisible by 11.
Find the Answers Pls

Answer 1

Answer:

Step-by-step explanation:

(i) A number is divisible by 2 if it is an even number. Greatest 2 digit even number is 98. ∴ A = 8

(ii) A number is divisible by 3 if the sum of its digits is divisible by 3 Sum of digits of 567A = 5 + 6 + 7+ A = 18 + A ∴ 18 is divisible by 3 ∴ A may be 0 The number will be 5670

(iii) A number is divisible by 6 if it is divisible by both 2 and 3 9A6 is even and so divisible by 2 If A = 9 then the sum of digits will be = 24 which is divisible by 3. The number will be 996 and A = 9

(iv) 08 is divisible by 4, so A08 is divisible by 4. If A = 1 then the sum of digits will be 9 which is divisible by 9. The number will be 108 and A = 1

(v) 5 + A + 2 – (8 + 5 + 2)  = 7 + A – 15  = -8 + A ∴ A = 8