Question

find (a+b) ➗ (a-b) = a=2/11,b=-3/8 ​

Answer 1

Answer:

$\frac{a + b}{a - b} \: \: if \: a = \frac{2}{11} and \: b = \frac{ - 3}{8}$

$a + b = \frac{2}{11} + \frac{ - 3}{8} = \frac{2 \times 8 + - 3 \times 11}{11 \times 8} = \frac{16 - 33}{88} = \frac{17}{88}$

$a - b = \frac{16 + 33}{88} = \frac{49}{88}$

$\frac{a + b}{a - b} = \frac{ \frac{17}{88} }{ \frac{49}{88} } = \frac{17}{49}$

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Answer 2

Step-by-step explanation:

$\frac{a + b}{a - b}$

$a + b \: = \frac{2}{11} + ( \frac{ - 3}{8} )$

$= \frac{2}{11} - \frac{3}{8}$

$= \frac{16}{88} - \frac{33}{88}$

$= \frac{16 - 33}{88}$

$\frac{ - 17}{88}$

$a - b = \frac{2}{11} - ( \frac{ - 3}{8} )$

$= \frac{2}{11} + \frac{3}{8}$

$\frac{16}{88} + \frac{33}{88}$

$\frac{16+ 33}{88}$

$\frac{49}{88}$

$\frac{a + b}{a - b} = \frac{ - \frac{17}{88} }{ \frac{49}{88} }$

$= \frac{ - 17}{49}$

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