Math, asked by sivanesh2008, 7 months ago

find (a+b)÷(a-b) if a = 1/2 b = 2/3​

Answers

Answered by sarasaradha85
10

Answer:

(a+b) ÷(a-b)

a=1/2

b=2/3

(a+b)÷(a-b)

(1/2+2/3)÷(1/2-2/3)

LCM=2,3=6

(1/3×3/3,2/3×3/3)÷(1/2-2/3)

(3/9+6/9)÷(1/2-2/3)

(3+4÷6) ÷(3-4÷6)

7/6 ÷

Answered by sourasghotekar123
6

Answer:

The answer to this given question is -7.

Step-by-step explanation:

  • Here, we are given with \frac{(a+b)}{(a-b)} and we need to solve this.
  • We are also given with the values of a and b. The value of a is \frac{1}{2} and value of b is \frac{2}{3}.
  • To solve the given algebraic equation we will substitute the value of a and b which are given to us.

\frac{(a+b)}{(a-b)}=\frac{\frac{1}{2} +\frac{2}{3} }{\frac{1}{2} -\frac{2}{3} }

We need to solve this in order to find the answer.

To solve this we first need to equal to the denominator of both numerator and denominator.

\frac{(a+b)}{(a-b)}= \frac{\frac{3+4}{6} }{\frac{3-4}{6} }

This is the equation after equaling the denominator on both numerator and denominator.

Further, solving it.

\frac{(a+b)}{(a-b)}=\frac{3+4}{3-4}  \\\frac{(a+b)}{(a-b)} =\frac{7}{-1} \\\frac{(a+b)}{(a-b)}=-7

Hence, after solving this given expression the answer is -7(negative seven).

#SPJ2

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