Find a, b and c such that the following numbers are in AP: a, 7, b, 23, c.
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Let the common difference be d.
Given a1 = a
a2 = > a + d = 7 --- (1)
a3 = > a + 2d = b --- (2)
a4 = > a + 3d = 23 --- (3)
a5 = > a + 4d = c ---- (4)
On solving (1) and (3), we get
2d = 16
d = 8.
substitute d = 8 in any on the above equations, we get a = -1.
substitute a = -1 in (2) we get b = -1 + 2(8)
b = 15.
substitute b = 15 in (4), we get c = -1 + 4(8)
c = 31.
The values of a = -1, b = 15, c = 31
Given a1 = a
a2 = > a + d = 7 --- (1)
a3 = > a + 2d = b --- (2)
a4 = > a + 3d = 23 --- (3)
a5 = > a + 4d = c ---- (4)
On solving (1) and (3), we get
2d = 16
d = 8.
substitute d = 8 in any on the above equations, we get a = -1.
substitute a = -1 in (2) we get b = -1 + 2(8)
b = 15.
substitute b = 15 in (4), we get c = -1 + 4(8)
c = 31.
The values of a = -1, b = 15, c = 31
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