Find A,B,C in the adjacent multiplication table A B C X A A _________ A C 6 C
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A B C
× A A
----------------------------
A² AB AC
A² AB AC
----------------------------------------------
A² A(A+B) A(B+C) AC
A² = A
A(A+B) = C
A(B+C) = 6
AC = C
from the last equation
AC = C
cancelling C from both sides;
A = 1
Now,
A(A+B) = C
1+B = C
and than A(B+C) = 6
B + C = 6
2B = 5
B = 5/2
C = 7/2
× A A
----------------------------
A² AB AC
A² AB AC
----------------------------------------------
A² A(A+B) A(B+C) AC
A² = A
A(A+B) = C
A(B+C) = 6
AC = C
from the last equation
AC = C
cancelling C from both sides;
A = 1
Now,
A(A+B) = C
1+B = C
and than A(B+C) = 6
B + C = 6
2B = 5
B = 5/2
C = 7/2
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