find a,b if(√2+√3)/(3√2- 2√3)=a+b√6
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(√2+√3)/(3√2- 2√3)
= 6 - 2√6 + 3√6 - 6
= 0 + 1√6
so, a= 0 and b=1
= 6 - 2√6 + 3√6 - 6
= 0 + 1√6
so, a= 0 and b=1
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