find a+b if 75a6b38 is divisible by 11
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Answer:
a+b=10
since the divisibility test of 11
is that the alternating sum of the digits of the number should be divisible by 11
therefore
7 - 5 + a - 6 + b - 3 + 8
a+b+1 should be divisible by 11
and lowest multiple that can have its sum expressed as sum of single digit numbers
a+b+1 = 11
a+b=10
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