Find a,b such that 18,a,b,-3 are in Arthimetic progressions
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Let d be the common difference of a.p
first term = 18
fourth term = a4 = -3
first term + 3d = -3
18 + 3d = -3
3d = -3 -18
3d = -21
d = -21/3
d = -7
Therefore ,
a2 - a1 = d
a - 18 = -7
a = -7 + 18
a = 11
a4 - a3 = d
-3 - a3 = -7
-3 + 7 = a3
4 = a3
Therefore ,
a = 11 ,
b = 4
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a=11
b=4
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