Question

Find a cubic function with the given zeros.

6, -3, 5

Answer 1

Answer:

f(x)=(x-6)(x+3)(x-5)=$x^3-8x^2-3x+90$.

Explanation:

Multiply together linear factors with each of these zeros i.e 6 , -3 and 5.

f(x)=(x-6)(x+3)(x-5)

Expand first two roots:

$f(x)=(x^2-3x-18)(x-5)$

Expand further:

$f(x)=x^3-8x^2-3x+90$.

Any polynomial in  x  with zeros(i.e 6 , -3, 5) will be a multiple (scalar or polynomial) of this f(x).

Therefore, the cubic function for the given zeros are: $f(x)=x^3-8x^2-3x+90$.

Answer 2

Answer:

Step-by-step explanation:idk