Question

find a cubic polynomial whose zeroes are 1,-2,3

Answer 1

Answer:

Step-by-step explanation:

(x-1)(x+2)(x-3)=(x^2+2x-x-2)(x-3)

=(x^2+x-2)(x-3)

=x^3-3x^2+x^2-3x-2x+6

=x^3-2x^2-5x+6