find a cubic polynomial whose zeroes are 1,-2,3
Answers
Answered by
2
Answer:
Step-by-step explanation:
(x-1)(x+2)(x-3)=(x^2+2x-x-2)(x-3)
=(x^2+x-2)(x-3)
=x^3-3x^2+x^2-3x-2x+6
=x^3-2x^2-5x+6
Similar questions