find a cubic polynomial whose zeros are 2, - 3 and 4
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We know that a cubic polynomial is in the form
ax3 + bx2 + cx + d
Now,
as we know that,
α+β+γ= -b/a
α.β+β.γ+α.γ= c/a
α.β.γ= -d/a
so, A/Q
α+β+γ= 3 = -b/a
α.β+β.γ+α.γ= -10 = c/a
α.β.γ= -24 = -d/a
as, a=1 we have,
b= -3
c= -10
d= 24
so, the equation is
x3-3x2-10x+24
ax3 + bx2 + cx + d
Now,
as we know that,
α+β+γ= -b/a
α.β+β.γ+α.γ= c/a
α.β.γ= -d/a
so, A/Q
α+β+γ= 3 = -b/a
α.β+β.γ+α.γ= -10 = c/a
α.β.γ= -24 = -d/a
as, a=1 we have,
b= -3
c= -10
d= 24
so, the equation is
x3-3x2-10x+24
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