Question

find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time And product of its zeroes are 3, -1/2, 5/4 respectively

Answer 1

Answer:

$2x {}^{3} - 6x {}^{2} - 1x - 10$

Step-by-step explanation:

$sum \: \: of \: zeroes = 3$

$sum \: of \: product \: of \: zeroes \: = \frac{ - 1}{2}$

$product \: of \: zeroes \: = \frac{5}{4}$

$so \: by \: the \: formula \: of \: cubic \: poly \\ nomial$

$x {}^{3} - (sum \: of \: zeroes)x {}^{2} + (sum \\ of \: product \: of \: zeroes)x - ( produ \\ ct \: of \: zeroes)$

$x {}^{3} - 3x {}^{2} - \frac{1}{2}x - \frac{5}{4}$

$take \: lcm$

$2x {}^{3} - 6x {}^{2} - 1x - 10$

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