Math, asked by shreyvimal2773, 1 year ago

Find a derivative of x square-2 at x=10

Answers

Answered by rita1608
0
ans:2x is the derivative of x square -2 and its value is 20 at x=10
Answered by HèrøSk
72

Answer:

f(x) = x ^{2}  - 2 \\ f(x + h) = (x + h)^{2} - 2 \\ Now, \\ \\  f'(x)=  \frac{f(x + h) - f(x)}{h}   \\ \displaystyle \lim_{h \to 0} =  \frac{(x + h)^{2} - 2 - (x^{2} - 2)}{h} \\ \displaystyle \lim_{h \to 0} =  \frac{x ^{2} + h^{2}  + 2xh-2 - x^{2}  + 2}{h} \\\displaystyle \lim_{h \to 0}  =  \frac{\cancel{x ^{2}} + h ^{2} + 2xh \: \cancel{ -2}  \:  \:  \: \cancel{-x^{2}} \: \cancel { + 2}}{h} \\ \displaystyle \lim_{h \to 0} =  \frac{h^{2} + 2xh }{h}  \\\displaystyle \lim_{h \to 0}  = h + 2x \\  = 0 + 2x \\  = 2x

f'(x) = 2x

f'(10) = 2*10

‎‎‎‎‎‎ ‎ ‎ ‎‎ ‎ ‎ ‎‎ ‎ ‎=20

Kindly thanks and rate 5 star✌️

Similar questions