Question

Find a formula for nth term. Of the sequence.1,1÷4,√3÷16,√5÷36,√7......​

Answer 1

Answer:

a = 1

common difference(d)= 1/4-1=-3/4

nth term = a+(n-1)

1 +(n-1)-3/4= 1+(-3n+3)/4

(4-3n+3)4= (7-3n)/4

hope ans is correct.....bye

Answer 2

In the sequence first term = 1
Common difference 1/4-1=-3/4
(Square root 3/16)-1/4=
(Sqrt3-4)/16
Common difference is not equal so given series not in AP