Question

Two dice are rolled simultaneously.Find the probability of (a) getting a sum of 5 (b) getting a number such that one is double of the other... Plz give me right ans. and yes answer is (not) 5/36...​

Answer 1

Answer:

Two dice are tossed

S={ (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

n(S)=36

Event A:- getting a sum of 5

A={(1,4),(2,3),(3,2),(4,1)}

n(A)= 4

P(A)=n(A)upon n(S)

= 4 upon 36

=1 upon 9

Event B:- getting a number such that one is double of the other

B= {(1,2),(2,4),(3,6)}

n(B)=3

P(B)=n(B)upon n(S)

=3upon 36

= 1/12

Explanation:

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