Question

4. Find the greatest number that will divide 1280, 1630,530 leaving the
remainders 4, 6, 8 respectively.​

Answer 1

Answer:

Let us first subtract the remainders from the given numbers as follows:

1630−6=1624

525−3=522

1280−4=1276

Now, let us factorize 1624,522 and 1276 as shown below:

1624=2×2×2×7×29

522=2×3×3×29

1276=2×2×11×29

We know that the largest positive integer which divides two or more integers without any remainder is called Highest Common Factor (HCF).

Therefore, the HCF of 1624,522 and 1276 is:

HCF=2×29=58

Hence, the largest number is 58.

Answer 2

Answer:

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