Question

find a if 6/3root2 - 2root 3 = 3 root 2 - aroot 3


full method with explanation
answer is 2....
I want explanation...

Follow me ​

Answer 1

Answer:

6/(3√2-2√3)

Here we have to rationalise the denominator,

Rationalising factor=(3√2+2√3)

=6/(3√2-2√3)×(3√2+2√3)/(3√2+2√3)

=6(3√2+2√3)/(3√2-2√3)(3√2+2√3)

=(18√2+12√3)/[(3√2)²-(2√3)²]

=(18√2+12√3)/(9(2)-4(3))

=(18√2+12√3)/18-12

=(18√2+12√3)/6

=(18√2/6)+(12√3/6)

=3√2+2√3

=3√2-(-2√3)

Compare this with 3√2-a√3

3√2-(-2√3)=3√2-a√3

Therefore, a= -2

Hope it helps...

Read more on Brainly.in - https://brainly.in/question/1196879#readmore