Find a number if 20 less than the number is equal to 3 times the sum and twice the number is 20
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Answer:
Let the Number be x
20 less than the Number = x - 20
Three times the Sum of twice and the Number = 3 ( 2x + 20 )
=> x - 20 = 3 ( 2x + 20 )
=> x - 20 = 6x + 60
=> 6x - x = - 20 - 60
=> 5x = - 80
=> x = - 80/5
=> x = - 16
=> x - 20 = 3 ( 2x + 20 )
=> - 16 - 20 = 3 { 2 × ( - 16 ) + 20 }
=> - 36 = 3 ( -32 + 20 )
=> - 36 = 3 ( - 12 )
=> - 36 = - 36
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