find a number such that it's excess over 50 may be greater by 11 than its defect from 89
Answers
Answered by
27
Let the number be x ,
According to the given conditions :
=====================
x-50 = (89-x) + 11
x-50 = 100-x
2x = 150
x = 75
___________________
Hence the number is 75.
According to the given conditions :
=====================
x-50 = (89-x) + 11
x-50 = 100-x
2x = 150
x = 75
___________________
Hence the number is 75.
Answered by
0
Answer :
75
Step-by-Step explanation:
50+x=(89+x) +11
50+x=100+x
2x=50
x=25
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