Math, asked by maneeshmadhu, 7 months ago

Find a number such that its excess over 50 may be greater by 11 than its defect from 89.

Answers

Answered by anuragcoolgupta
0

Answer:

75

Step-by-step explanation

Let the number be x. Then according to question, the linear equation formed is: (x - 50) - (89 - x) = 11. Now, solving the equation we get x (required number) is 75.

Answered by ritika707
0

Answer:

75

Step-by-step explanation:

Let the number be x,

according to the given conditions :

x-50 = (89-x) + 11

x-50 = 100 - x

2x = 150

x = 75

Ans is 75

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