Find a number such that its excess over 50 may be greater by 11 than its defect from 89.
Answers
Answered by
0
Answer:
75
Step-by-step explanation
Let the number be x. Then according to question, the linear equation formed is: (x - 50) - (89 - x) = 11. Now, solving the equation we get x (required number) is 75.
Answered by
0
Answer:
75
Step-by-step explanation:
Let the number be x,
according to the given conditions :
x-50 = (89-x) + 11
x-50 = 100 - x
2x = 150
x = 75
Ans is 75
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