Question

find a number such that when 5 is subtract from 5 times the number the result is 4 more than a numbet​

Answer 1

Answer:

9/4 is the value of number

Step-by-step explanation:

Let the number be x.

According to the question,

5x-5=4+x

5x-x=4+5

4x=9

x=9/4

Hope It Helps

Answer 2

Answer:

$\large\boxed{\sf{\dfrac{9}{4}}}$

Step-by-step explanation:

Let the required number be "x"

Now, according to question,

5 subtracted from 5 times the number results 4 more than the number.

Therefore, forming a linear equation, we get,

$= > 5x - 5 = x + 4$

To find the number,

Let's solve the linear equation formed.

Firat of all, subtracting x from both the sides.

Therefore, we will get,

$= > 5x - x - 5 = x + 4 - x \\ \\ = > 4x - 5 = 4$

Now, adding 5 on both the sides, we get,

$= > 4x - 5 + 5 = 4 + 5 \\ \\ = > 4x = 9$

Now, divide both sides by 4, we get,

$= > \dfrac{4x}{4} = \dfrac{9}{4} \\ \\ = > x = \dfrac{9}{4}$

Hence, the required value of x = 9/4