Question

find a number such that when 7 is subtracted from 3 times the number the result is 9 more than twice​

Answer 1

Answer:

Let the number be x.

Then according to the problem,

5x−5=2x+4

or, 3x=9

or,x=3.

So the number is 3.

Answer 2

Answer:

The required number is 16.

Step-by-step explanation:

Algebraic expression:

• A polynomial which contains variables, coefficients and constants joined together using mathematical operations such as addition, subtraction, multiplication and division is called as algebraic expression.

Algebraic equation:

• An algebraic equation is a mathematical statement that contains two equated algebraic expression.
• The general form of algebraic equation is P=0 or P=Q where P and Q are polynomials.

Let the number be x.

• 3 times the number is 3x.
• 7 is subtracted from the product is 3x-7.
• twice of number is 2x.
• 9 more than twice of number is 2x+9.

As per the given condition,

when 7 is subtracted from 3 times the number the result is 9 more than twice of the number.

 mathematically it can be expressed as

                3x-7 = 2x+9

                3x-2x = 9+7

                       x = 16

             Hence, the required number is 16.

Know more about Solving Algebraic equations:

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