Find a number which when divided by {(3)^-1+(2)^-1} gives the quotient as {(6)^-1+(3/2)^-1}^-1 ?
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5
Answer:
1
Step-by-step explanation:
Divisor = (3⁻¹ + 2⁻¹) , Quotient = [6⁻¹ + (3/2)⁻¹ ] ⁻¹ , Remainder = 0
= (1/3 + 1/2) = (1/6 + 2/3)⁻¹
= 5/6 = (5/6)⁻¹ = 6/5
∴ Quotient x Divisor + Remainder = Dividend
⇒ 5/6 X 6/5 + 0 = Dividend
⇒ Dividend = 1
Hope this helps u ;) !!
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