Question

Find a number which when divided by 43 gives 3 as the quotient and 6 as the remainder .​

Answer 1

The answer is 135

Step-by-step explanation:

Let the number be x(dividend)

Given, Divisor = 43, Quotient = 3 & Remainder = 6

Since, Dividend = Divisor*Quotient+Remainder

So, x=43*3+6

or, x= 129+6

or, x=135

Hence the required number is 135

This is the answer....

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Answer 2

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